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Why is the angular dimension of the moon so close ...

Why is the angular dimension of the moon so close to the angular dimension of the sun (the moon covers almost perfectly the sun during eclipse)?  Is there a theory for this or is it simply a co-incidence?


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I wouldn't wanna be in a club that wouldn't let me in...

It's not that the dimensions are the same, it's that they seem the same to us from earth.  Our view of the moon is because of the light that is reflected into it by the sun.  We cannot see the moon without the light of the sun.  The sun is very far away and doesn't seem very big when we see it in the sky, therefore when the moon (which is many light years closer) gets in the way of our view of the sun, we see an eclipse. 

Posted 2007-11-12T20:04:04Z
 
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thanks but it does not seem to be the right answer.  It is obvious that the dimensions of the sun and moon are not the same (that is why i asked about angular dimension).  It is also not correct to say that the moon is many light years closer than the sun because the sun distance from earth  is only a few minutes of light (and not years of light).

thanks anyway - huro 

 
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It looks more like a coincidence to me. A theory about it would start like this: if A orbits B and B orbits C, would A and C appear to be of similar size when viewed from B?.  I can not see a connection between the size of the moon and its orbit. If it was just the size of a tennis ball it could evolve on the same orbit, but its angular size would be much smaller.

Posted 2007-11-17T21:14:28Z
 
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Ignorance can be cured, but stupidity lasts forever.

The moon is 250,000 miles away and has a diameter of 2,000 miles. The sun is 93,000,000 miles away and has as a diameter of 870,000. The fact that they appear to be the same size from earth has to do with the ratios of sizes and diameters and is nothing but a huge cosmic coincidence.

Posted 2008-09-08T16:09:25Z
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