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Required force of sled

What force is required to accelerate a sled with a mass of 150 Kg at a rate of 0.71 m/s?


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All in all, I'd rather be in Cleveland.

Since we don;t know any different, we have to assume that the snow/ice adds no resistance/friction to fight your push, and also that the surface is level ... no uphill or downhill.  Just a level, frictionless surface.

The formula to remember is  [ F= m A ].  Force = (mass) times (acceleration).

You said mass = 150 and acceleration is 0.71 m/sec-squared.

So Force = 150 x 0.71 = 106.5 kgm-meters / sec-squared,                             which is called 106.5 newtons .

For folks more comfortable with English/Imperial ...  The sled weighs about 331 pounds ( ! ), and the required push is about 24 pounds.
Posted 2009-11-16T04:03:49Z
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Ian
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Yes,

F (Newtons) = m (kg) x a (m/s^2) = 150 x 0.71 = 106.5 Newtons 

Regards - Ian
Posted 2009-11-20T12:14:41Z
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This could be a trick question.  If the sled has a velocity of 0.71 m/s, it is not accelerating, which means there is not net force acting on the object.  So don't push it!

LOL
Posted 2009-11-21T09:57:07Z
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