PLZ any one help dis question...?

An open top rectangular storage tank has a volume of 8 cubic units. Your task, as a designer, is to find the dimensions of tank such that the surface area of the tank is minimised, thus minimising construction material costs.

 

i)When you have found the dimensions you should have found that the length and width have the same value by symmetry. What is this common value

ii)What is the value of the height of the tank?

iii)Find the minimum surface area of the contruction material required

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6712 thumbs up

Love is the battery of life....

Hi,


The minimum surface area to a volume of 8 cubic volume is a sphere.... since you asked for a rectangulr shape the nearest to a sphere is a cube.  So the dimensions should be 2 x 2 x 2.   The volume is 8 cubic ..... and the surface area is 12 square......  You'll reach the same answer via derivatives.  
V = X * Y * Z      (V=8)    S = 2 (X + Y + Z)
Best regards,

Posted 9 months ago ( permalink )
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Let's use the Lagrange technique: Define "x"=width=length "y"=height. Thus (x^2)y=8 -> (x^2)y-8=0. This is the constrainment. The expression we need to minimize is ("z"=surface area) z=(x^2)+4xy. According to the technique we should now build the equation (x^2)+4xy-L[(x^2)y-8]=0 ["L"=Lagrange Variable].  The next step is to use a gradient on the latter equation and to look for critical points on equation with 0. So together with the constrainment we'll have 3 expressions:

(x^2)y=8

2x+4y-2xyL=0 

4y-Lx^2=0 

You should now solve these equations and substitute the numbers to the "z" equation. The last step is to choose the minimal result.

I'm sorry I couldn't bother to solve the equations.


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i) 2 ii) 2 iii) 20 (Bottom (4) + 4 sides (each 4))


Posted 9 months ago ( permalink )
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markpx was invited by Yedda to answer this question.

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